🎨 #4078 【小程序】获取手机号的方法支持openid校验
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@@ -17,8 +17,10 @@ public class DataUtils {
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*/
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public static <E> E handleDataWithSecret(E data) {
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E dataForLog = data;
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if (data instanceof String && StringUtils.contains((String) data, "secret=")) {
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dataForLog = (E) RegExUtils.replaceAll((String) data, "(^|[?&])secret=[^&]*", "$1secret=******");
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if (data instanceof String) {
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String stringData = (String) data;
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stringData = RegExUtils.replaceAll(stringData, "(^|[?&])secret=[^&]*", "$1secret=******");
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dataForLog = (E) RegExUtils.replaceAll(stringData, "(\\\"openid\\\"\\s*:\\s*\\\")[^\\\"]*(\\\")", "$1******$2");
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}
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return dataForLog;
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}
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@@ -47,4 +47,14 @@ public class DataUtilsTest {
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assertFalse(s.contains("%2F"), "Encoded characters in the secret must be masked too");
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assertTrue(s.contains("&secret=******&"), "Secret should be replaced with asterisks");
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}
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@Test
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public void testHandleDataWithOpenidInJson() {
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String data = "{\"code\":\"phone-code\",\"openid\":\"user-openid\"}";
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String result = DataUtils.handleDataWithSecret(data);
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assertFalse(result.contains("user-openid"));
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assertTrue(result.contains("\"openid\":\"******\""));
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}
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}
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